how can I use logarithms to compare a,b,c in an ascending order $$a=\frac{3^{8.7} - 3^{6.2}}{5}\\\ b=\frac{3^{11.7} - 3^{8.7}}{6} \\\ c=\frac{3^{11.7} - 3^{6.2}}{11} \\\ $$ i tried to simplify a b and c to get a constant that won't effect the compression which was in this case $3^{6.2}$ and compared a and b then a and c then calculated both b and c to rank them from highest to lowest $$\\\ a=\frac{3^{6.2}(3^{2.5} - 1)}{5}\\\ b=\frac{3^{6.2}(3^{5.5} - 3^{2.5})}{6} \\\ c=\frac{3^{6.2}(3^{5.5} - 1)}{11} $$ but the lesson is about logarithms and when I added log to a b and c I could not really simplify it down
2026-05-06 07:40:48.1778053248
how to solve the following question using logarithms?
106 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2

Your second version of the definitions makes clear that the term subtracted is rather small compared to the first term and the three expressions are not close enough for it to matter. You can also divide out the common factor $3^{6.2}$ as that will not change the ordering. Now you can use logs to compare the difference in the power of $3$ to the difference in the denominators to find the order.