$$\begin{cases}xy + \frac{4}{xy} = 4 \\ 2x-y \; \;= 4 \end{cases}$$
I just defined y, but still can not proceed, please help.
$$\begin{cases}xy + \frac{4}{xy} = 4 \\ 2x-y \; \;= 4 \end{cases}$$
I just defined y, but still can not proceed, please help.
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Hint:
Rearrange the first equation to find $(xy-2)^2=0\iff xy=2$
$$4=2x-y=2x-\dfrac2x$$
Rearrange to form a Quadratic equation in $x$