How to solve this absolute value equation and summation question??

Question

$$|2x − 3| − |x + 2| = 5$$

I have no idea. I didn't see anything like this in class. It is a practice question and something like it will come up on the exam can someone please show me the full solution and working (that is how I learn) Thanks in advance.

Answer 1

Hint: using the definition of the absolute value we get $$|2x-3|=\begin{cases} 2x-3, & 2x-3\geq 0 \\ -(2x-3), & 2x-3<0 \end{cases}=\begin{cases} 2x-3, & x\geq \frac{3}{2} \\ -2x+3, & x<\frac {3}{2}\end{cases}$$ $$ |x+2|=\begin{cases} x+2, & x+2\geq 0 \\ -(x+2) & x+2<0 \end{cases} = \begin{cases} x+2, & x\geq -2 \\ -x-2, & x<-2\end{cases}$$

This is all we need to simplify the equation. "Something happens" at $x=-2$ and $x=\frac{3}{2}$, one of the terms $|2x-3|$ or $|x+2|$ will change there. Using this we get 3 cases we have to consider:

1. $x<-2$
2. $-2\leq x < \frac{3}{2}$
3. $\frac{3}{2}\leq x$

Answer 2

Hint

if $x \geq 0$ then you would have $$2x-3 -(x+2) = 5$$

if $x < 0$ then you would have $$-(2x-3) +(x+2) =5$$

Answer 3

Note that for all $x \geq 3/2$ we have $|2x-3| - |x+2| = 5$ if and only if $x-5 = 5$, i.e. $x = 10$; for all $-2 \leq x < 3/2$ we have $|2x-3| - |x+2| = 5$ if and only if $-3x = 4$, i.e. $x = -4/3$; for all $x < -2$ we have $|2x-3| - |x+2| = -x + 5 = 5$, i.e. $x = 0$.