How to solve this cubic equation? $x^3 -3x^2+ 4 = 0 $

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I am having trouble solving this cubic equation. It seems that none of the tricks I learned before are working.

Find all values of $x$:
$$x^3 -3x^2+ 4 = 0 $$

1

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It follows from the rational root theorem that if the equation has a rational root, then it must be one of the numbers $\pm1$, $\pm2$ or $\pm4$. And it is easy to see that $2$ is indeed a root. Can you take it from here?