Lets say I have this
$H = W*F*W'$
where all matrices are 2x2 and $F$ is a diagonal matrix.
$H$ and $F$ is known. Ho solve get $W$ in algebraic form?
I tried this here:
$inv(W)*H*inv(W') = F$ but it seems wrong... Its not homework.
Lets say I have this
$H = W*F*W'$
where all matrices are 2x2 and $F$ is a diagonal matrix.
$H$ and $F$ is known. Ho solve get $W$ in algebraic form?
I tried this here:
$inv(W)*H*inv(W') = F$ but it seems wrong... Its not homework.
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Hint 1:
You can pre-multiply both sides of an equation by the same conformable term. So of you have
$$ X = AB $$ you can do $$ A^TX = A^TAB $$ or $$ XB^T = ABB^T $$
Hint 2:
If you have $X$ and you want to to go away, you can multiply it by $X^T(X^TX)^{-1}$
I suggest that you play around numerically to confirm the algebra. Here's something to get you started: