Fresh fruits contain 75% while dry fruits contain 20% water. If the weight of dry fruits is 300 kg what was its total weight when it was fresh?
Doubt: I really do not understand what to equate.
2026-04-01 08:09:05.1775030945
How to solve this problem on percentage calculation?
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Let $x_1 = 300$ (kg) and let $x_2$ be the total mass you are looking for.
From your first sentence, you can write $(1-0.75)x_2 = (1-0.20)x_1$. This is the ratio of pure fruits they both have. So from $x_1$, $80$% is pure fruit, which is $240$. This gives $0.25x_2 = 240$, which leads to $x_2 = $ total mass $ =960$kg