The problem is to find $x$ and $y$. $$\sqrt x + y = 7$$ $$\sqrt y +x = 11$$ I know what the answer is, but I am confused about how to get the answer. Here’s the picture of the problem: https://m.imgur.com/gallery/7Q8asNU
2026-04-17 21:56:58.1776463018
How to solve this problem? You got to find $x$ and $y$.
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$$\sqrt{x}=7-y$$
$$\sqrt{y}=11-x$$
Square both sides of each:
$$x=49-14y+y^2$$
$$y=121-22x+x^2$$
Substitute the first equation into the second:
$$y=121 -22(49-14y+y^2) + (49-14y+y^2)^2$$
And you have a quartic in $y$. Be careful with the solutions that you get, though. Squaring both sides can create extra solutions to the equation so you'll need to substitute them back into the your original system to check which ones are valid.