$$ \sum_{n=1}^{\infty} \frac{\ln(n)^6}{n+3}$$
I know that the series is divergent , But how can show through comparison test the series is divergent? I just want hint. Thanks
2026-04-14 19:14:30.1776194070
How to solve using Comparison test , I just want hint
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Hint: $n>2\implies\log(n)>1$