|2x + 5| ≤ |x + 3| I have the answer listed in front of me but it's not helping me figure out how to get there.
2026-03-12 16:27:08.1773332828
How to solve with steps (simple absolute value synthesis) |2x + 5| ≤ |x + 3|
17 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
1
One way to solve this is to square both sides:
$$(2x+5)^2\le (x+3)^2$$
$$4x^2+20x+25\le x^2+6x+9$$
$$3x^2+14x+16\le 0$$
$$(3x+8)(x+2)\le0.$$
If a product of two terms is negative, one is negative and one is positive.
Can you take it from here?