Any help would be appreciated. :)
I tried splitting the equation about $x=3$, but the terms $x^2$ and $2^x$ Together in the equation(s) are troubling me.
I don't know why I'm unable to apply the property $log_ax=\frac1{log_xa}$
2026-04-11 16:50:44.1775926244
How to solve: $x^22^{x+1} + 2^{|x-3|+2} = x^22^{|x-3|+4} + 2^{x-1}$
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1
HINT
I would say
$x^2 2^{x+1} + 2^{|x-3|+2} = x^2 2^{|x-3|+4} + 2^{x-1}$ |*2
$4x^2 2^{x} + 2^{|x-3|+3} = 4x^2 2^{|x-3|+3} + 2^{x}$
$4x^2 (2^{x} -2^{|x-3|+3})-(2^{x} -2^{|x-3|+3}) = 0$
$(4x^2 -1) (2^{x} -2^{|x-3|+3}) = 0$