I am starting to learn about the Calculus of Variations and the Euler-Lagrange equation is extremely confusing to me:
The Euler–Lagrange equation, then, is given by $$L_x(t,q(t),q'(t))-\frac{\mathrm{d}}{\mathrm{d}t}L_v(t,q(t),q'(t)) = 0.$$ where $L_x$ and $L_v$ denote the partial derivatives of $L$ with respect to the second and third arguments, respectively.
Specifically, I don't understand the meaning of: $$L_x = \frac{\partial L(t, q, q')}{\partial q}$$
I'm confused because $q$ and $q'$ are both functions of $t$, but taking a partial derivative requires that we hold other parameters constant.
Yet $t$ is a parameter of $L$ as well. Thus when differentiating $L$ with respect to $q$, we hold $t$ constant.
But if $t$ is constant then doesn't that mean $q$ and $q'$ are constant?
And hence mustn't the derivatives $L_x$ and $L_v$ both be equal to zero?
While we write $L$ as $L(t,q(t),q'(t))$, it is really just a function of three variables. We could just as easily write it as $L(x,y,z)$ and, when evaluating $L$ on a given function $q$, substitute $t$ for $x$, $q(t)$ for $y$, and $q'(t)$ for $z$. However, this could lead to some confusion and lots of extra notation, so it is not usually done.
So, when taking the partial derivative $\frac{\partial L}{\partial q}$, we can just ignore any relations between $q$ and $q'$ and treat them as totally separate variables.