On Berger's 《A Panoramic View of Riemannian Geometry》 I read an explanation of curvature which is new to me.
He writes
'For a geometric curve, we can introduce it(curvature) by looking at the variation of the length of the curves drawn at a constant distance, called the parallel curves.If the absolute value of the infinitesimal change of length of these equidistant curves, close to a point $m = c(t)$, is the same as for a circle of radius r we say that the curve c has radius of curvature r at $m = c(t)$, and that its curvature is $K = 1/r$.'
I'm not familiar with the 'variation' he said.In fact the 'variation' he mentioned in the previous section means two points $p(t)$ and $q(t)$ running along two curves in the Euclidean plane, and we watch how the distance $d (p (t), q (t))$ varies with time t.But I can not understand in the context of curvature.
Any help will be thanked.
This is not so complicated. If we take an arclength-parametrized plane curve $\alpha(s)$, then the family of parallel curves Berger is talking about is given by $\beta_\epsilon(s) = \alpha(s) - \epsilon N(s)$, where $N$ is the principal normal. (I chose the negative sign so that the parallel curves move outward as $\epsilon$ increases.) ($s$ is arclength for $\alpha$, but not for $\beta$.) Then we have $\beta'_\epsilon(s) = (1+\epsilon\kappa(s))T(s)$, and so the arclength of $\beta$ comes from integrating $|1+\epsilon\kappa(s)| = 1+\epsilon\kappa(s)$. Then the variation — or rate of change — of an infinitesimal amount of arclength of $\beta_\epsilon$ is $$\frac d{d\epsilon}\Big|_{\epsilon = 0} (1+\epsilon\kappa(s)) = \kappa(s).$$