How to use epsilion delta limit definition to proof the limit of x^x as x approaches to 0 is 1

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$\lim\limits_{x\rightarrow 0}{x^x}=1$

What value can the $\delta$ be?

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How about: pick any $x$ close to $0$, say, $\frac{1}{10^k}$,

$(\frac{1}{10^{k}})^{(\frac{1}{10^{k}})} = 10^{-\frac{k}{10^{k}}}$

Notice how as $k$ grows larger (and your $x$ gets closer to $0$), that exponent (on the RHS) gets closer and closer to zero. What is $\lim_{n\to 0} 10^{n}$?