How to use Taylor 's formula to evaluate $\lim_{x\to 0}\frac {e^x \sin x -x (1+x)}{x^3}$

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Use Taylor 's Formula to evaluate the following limit: $$\lim_{x\to 0}\frac {e^x \sin x -x (1+x)}{x^3}.$$

Could anyone help me in solving this please?

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Hint: The Taylor series of $e^x\sin(x)$ about $0$ is $x+x^2+\frac{x^3}3+\cdots$