
I'm not exactly sure how to do this. I know the answer is $£64,000$ but whatever I try, nothing is working.
i.e. $£80,000$ x $25%$ $= 2,000,000$ devided by $100$ $=$ $20,000$
$£80,000 - £20,000 = £60,000$

I'm not exactly sure how to do this. I know the answer is $£64,000$ but whatever I try, nothing is working.
i.e. $£80,000$ x $25%$ $= 2,000,000$ devided by $100$ $=$ $20,000$
$£80,000 - £20,000 = £60,000$
On
This is saying for a number $x$, if it increased by 25%, then it totals to $$\$80,000$$
So we can say that:
$$x + 0.25x = \$80000$$ $$1.25x = \$80000$$ $$x= \$64000$$
So your answer is $\$64000$.
On
Just to add to Varun
$$x+0.25x=80000,$$
which is the same as saying $1.25x = 8000$, therefore
$$x = \frac{80000}{1.25} = 64000.$$
On
Recall that $25\% = \dfrac{25}{100} = 0.25$.
So we have some amount, $x$, that when increased by $25\%$ is equal to $80,000$.
Translating into math: $$x + 0.25 \times x = 80,000 \iff 1.25 x = 80,000 \iff x = \dfrac{80,000}{1.25} = 64000$$
On
What you're asking is this:
125% of what is 80,000?
Algebraically:
- 1.25x = 80,000
- Divide both sides by 1.25:
12.5x/1.25 = 80,000/1.25- Simplify: x = 64,000
x = 64,000 is the answer you're looking for, i.e., the price of the house a year ago.
Check to see that that is right:
Calculate a 25% increase on 64,000:
25% x 64,000 =16,000
Add that increase to last year's price:
64,000 + 16,000 = 80,000
80,000 is this year's price, so it looks good.
Let's call $x$ the value of the houses one year ago. So you have:
$$1.25 \cdot x = 80.000$$
Because the value of the houses now is a $25\%$ increase over the value of the houses one year ago ($x$).
Solving for $x$ gives you the correct value.