A set of propositional formulas $P_1, \cdots, P_k$ is consistent iff there is an environment in which they are all true.
Write a formula, $S$, so that the set $P_1, \cdots, P_k$ is not consistent iff $S$ is valid.
Sorry for asking this homework question. I really don't know how to solve it.
Let $S := \lnot (P_1 \land \ldots \land P_k)$.
If $\{ P_1, \ldots, P_k \}$ is inconsistent (i.e. unsatisfiable), then $(P_1 \land \ldots \land P_k)$ is always false, and thus its negation is a tautology (i.e. valid).
If $S$ is valid, then $(P_1 \land \ldots \land P_k)$ is always false (a contradiction) and thus there is no truth assignment that can simultaneously satisfy all the $P_i$'s, i.e. $\{ P_1, \ldots, P_k \}$ is unsatisfiable (i.e. inconsistent).
According to your post
Thus, inconsistent (the negation of consistent) means that there is no truth-assignment for which the formulas are all true.
This in turn means that there is no truth-assignment that simultaneously satisfies all formulas, and this amounts to saying that the set of formulas is unsatisfiable.