Write this expression in sigma notation:
$$\frac 1{2k} + \frac 2{3k} + \frac 3{4k} + \ldots + \frac{k-1}{k^2} + \frac 1{k+1}.$$
Write this expression in sigma notation:
$$\frac 1{2k} + \frac 2{3k} + \frac 3{4k} + \ldots + \frac{k-1}{k^2} + \frac 1{k+1}.$$
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$$\sum\limits_{i=1}^k \dfrac i {(i+1)k}$$
(Note that when $i=k-1$ the summand simplifies to $\dfrac{k-1}{k^2}$,
and when $i=k$ the summand simplifies to $\dfrac1{k+1}$.)