Is there a way to integrate:
$e^{e^x}$
without using a Taylor or McLaurin Series expansion?
$$\int e^{e^x}\,\mathrm{d}x$$
Let $t=e^x\implies\mathrm{d}t=e^x\mathrm{d}x=t\mathrm{d}x\implies \mathrm{d}x=\frac{\mathrm{d}t}{t}$
$$\int \frac{e^t\mathrm{d}t}{t}=\int\frac{\mathrm{d}(e^t)}{t}$$
$$\operatorname{Ei}(t)+c=\operatorname{Ei}(e^x)+c$$
$\operatorname{Ei}(x)$ is the exponential integral.
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$$\int e^{e^x}\,\mathrm{d}x$$
Let $t=e^x\implies\mathrm{d}t=e^x\mathrm{d}x=t\mathrm{d}x\implies \mathrm{d}x=\frac{\mathrm{d}t}{t}$
$$\int \frac{e^t\mathrm{d}t}{t}=\int\frac{\mathrm{d}(e^t)}{t}$$
$$\operatorname{Ei}(t)+c=\operatorname{Ei}(e^x)+c$$
$\operatorname{Ei}(x)$ is the exponential integral.