How would I solve for a rate that compounds m times per annum?

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Please excuse me, this is my first time using the site and I have absolutely no idea what I'm doing with the notation. Anyways, I am attempting to prove that:

$$R_m = m\left(e^{\frac{R_c}{m}}-1\right)$$

Where...

$$R_c = m\left(ln\left({1+\frac{R_m}{m}}\right)\right)$$

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$e^{\frac{m(ln(1+\frac{R_m}{m}))}{m}} \rightarrow e^{ln(1+\frac{R_m}{m})} \rightarrow 1+\frac{R_m}{m}$

Plugging it back into the larger equation

$m(1+\frac{R_m}{m}-1) \rightarrow R_m$