how would you modify the equation
a - b = c
so that 'c' could not be less than zero. e.g.
5 - 3 = 2
5 - 4 = 1
5 - 5 = 0
5 - 6 = 0
5 - 60 = 0
how would you modify the equation
a - b = c
so that 'c' could not be less than zero. e.g.
5 - 3 = 2
5 - 4 = 1
5 - 5 = 0
5 - 6 = 0
5 - 60 = 0
On
The following equation requires $c$ to be non-negative: $a^2 + b^2 = c$ where $a,\,b,\,c \in \mathbb{R}$.
On
Well if $a-b=c$ and you require that $c\geq 0$ then you require that $a-b\geq 0$ which means you require $a\geq b$. Interpreting your question another way, you can also do
$$|a-b|=c$$
so $c$ will never be negative. Looking at your examples, you can also do
$$\max(a-b,0)=c$$
which coincides exactly with your numerical examples.
First, you are talking about an inequality which can be stated as thus:
$c\ge0$
Second, the equation $a-b=c$ doesn't state what number system are these numbers from: Natural numbers, Whole Numbers, Integers, Rationals, Reals, Complex, Algebraic, or some other number system? There are more than a few sets of possible numbers so this is something to consider when asking a question.
Third, $5-60=-55$ which does exist in the Integers, Reals, Algebraic, Rationals and a few other number systems. To say that c can't be less than zero but is an integer would be to simply make it a Whole Number in terms of an English statement that is equivalent to the inequality I stated above.