I calculated the vector magnitude and angle but the text book I got it from stated the latter is different.

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Assume the following fact: If an airplane flies with velocity V(a) relative to the air and the velocity of the wind is W then the velocity vector of the plane relative to the ground is V(g) = W + V(a).

Now suppose that the Wind is blowing from the North-East at 50 mi/h and that the pilot wishes to fly due East at 500 mi/h. What should the plane's apparent velocity vector V(a) be?

My issue with this problem, isn't that I didn't get an answer at all, I got a vector of magnitude 537 approximately which is correct, but I got an angle of around 4 degrees but the text book says that its 86 degrees. I can't find where I went wrong in that calculation. Any help you can offer will be greatly appreciated.

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Notice that the coordinate system has the zero angle in the North direction. Going to East is at $90^\circ$. My guess is that you calculated that you have $4^\circ$ angle with respect to the East direction. The angle with respect to North is $90^\circ-4^\circ=86^\circ$