I'm stuck on solving (4)(ii) and 4(b), I have tried to solve them but got stuck in the middle, any hints?
This is where I have gotten in (4)(a)(ii) and (4)(b)(i), I have no idea how to start solving on (4)(b)(ii)
I'm stuck on solving (4)(ii) and 4(b), I have tried to solve them but got stuck in the middle, any hints?
This is where I have gotten in (4)(a)(ii) and (4)(b)(i), I have no idea how to start solving on (4)(b)(ii)
Copyright © 2021 JogjaFile Inc.


For 4aii), Remember your Laplace transform properties and notice that
$$ \frac{\mathrm{d}}{\mathrm{d}s}\frac{s}{s^{2}+4} = -\frac{s^{2}-4}{(s^{2}+4)^{2}},$$
motivating the manipulation
$$ \frac{s^{2}}{s^{2}+4} = \frac{1}{2}\left(\frac{s^{2}-4}{(s^{2}+4)^{2}} + \frac{s^{2}+4}{(s^{2}+4)^{2}}\right).$$
Alternatively, you can compute the Bromwich integral
$$ f(t) = \frac{1}{2\pi i}\lim_{R\to\infty}\int_{a-iR}^{a+iR}\frac{s^{2}}{(s^{2}+4)^{2}}\,e^{st}\,\mathrm{d}s.$$
It involves finding the residues of the second-order poles at $s = \pm 2i$ and summing them.
4bi) is similar. Notice that
$$ \frac{9}{(s^{2}+9)^{2}} = \frac{1}{2}\left(\frac{9+s^{2}}{(s^{2}+9)^{2}} + \frac{9-s^{2}}{(s^{2}+9)^{2}}\right).$$