How would you estimate how much all the ice in a skating rink weighs? Use variables like D for depth, L for length, and such.
I am just stumped because if you get the volume, you turn it into mass, you will essentially have the mass of a cube, how can I change that to make it the mass of ice. With the desity or something like that?
I would also approximate the ice in the rink as a volume of a rectangle. V=LWH According to this site:
http://www.dimensionsinfo.com/ice-rink-dimensions/
30 m by 60 m is the size of the official Olympic games rink with an average of 2.5 cm for the thickness of the ice.
And as 1m is 100cm, 60m is 6000cm and 30m is 3000cm
Using the volume formula we get $V= 4.5\times10^7 cm^3$ for the ice.
Now plugging this into the density equation to get mass we get,
$M = 4.125\times10^4 kg$