Ideal of the ring of upper triangular matrices

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Let $S=\left\{\begin{bmatrix}a&b\\0&c\end{bmatrix}: a,b,c\in \mathbb{R} \right\}$ be a ring under matrix addition and multiplication. Then the subset $P=\left\{\begin{bmatrix}0& p\\ 0&0\end{bmatrix}:p\in \mathbb{R}\right\}$ is

  1. not an ideal of $S$
  2. an ideal but not a prime ideal of $S$
  3. is a prime ideal but not a maximal ideal of $S$
  4. is a maximal ideal of $S$.

It is obvious that $P$ is an ideal of $S$. So all we need to determine is whether it is prime ideal or maximal ideal of $S$. Now we see that- $$\begin{bmatrix}0&a\\0&0\end{bmatrix}\begin{bmatrix}0&0\\0&a\end{bmatrix}\in P$$ but $\begin{bmatrix}0&0\\0&a\end{bmatrix}\notin P$. Here I have a minor confusion. For and ideal to be a prime ideal, if $ab\in P$ then either $a$ or $b$ has to be in $P$. In this case, the above mentioned matrix is not in $P$, does it implies $P$ is not a prime ideal? Also I don't know how to show $P$ is maximal or not. So can anyone help me on this? Thanks.

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This is a fix of a horribly wrong first attempt - thanks to @rschwieb for notifying me.

We are taking the following definition of prime ideal in a possibly non-commutative ring.

The ideal $P$ of the ring $S$ is prime iff for each $x, y \in S$, if $x S y \subseteq P$, then either $x \in P$ or $y \in P$.

We have $$ x = \begin{bmatrix}1&0\\0&0\end{bmatrix} \notin P \qquad y = \begin{bmatrix}0&0\\0&1\end{bmatrix} \notin P, $$ but $$ x \begin{bmatrix}a&c\\0&b\end{bmatrix} y = \begin{bmatrix}0&c\\0&0\end{bmatrix} \in P $$ for all $\begin{bmatrix}a&c\\0&b\end{bmatrix} \in S$.

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$P$ is not a prime ideal. Consider for example the homomorphism of rings $$ S\longrightarrow \mathbb R\times \mathbb R,\quad \begin{bmatrix}a & b\\ 0 & d\end{bmatrix} \longmapsto (a,d), $$ where the operations on $\mathbb R\times \mathbb R$ are componentwise. This homomorphism is clearly surjective with kernel $P$. Hence $S/P\cong \mathbb R\times \mathbb R$, which is not an integral domain. Therefore, $P$ is not a prime ideal (and in particular not maximal).