I want to show the following result directly:
Let R be a regular ring then every ideal is the intersection of maximal ideals containing it.
I know that every ideal of a regular ring is a z-ideal (semiprime), which are intersection of prime ideals, but every prime ideal in a regular ring is maximal and thus the above result follows. See G.Mason z-ideals and prime ideals. But I do not want to use the above direction of proof. Help me get a direct proof.
Suppose $R$ is VNR and let $I$ be a proper ideal.
Then $R/I$ is VNR too.
VNR rings are semiprimitive, so the zero ideal of $R/I$ is the intersection of maximal ideals of $R/I$.
By correspondence, $I$ is the intersection of maximal ideals of $R$ containing $I$.
QED