Here is the exercise:
Let $A$ be a $5\times5$ complex matrix such that $(A-2)^3(A+2)^2=0$, where we define $A-\mu:=A-\mu I$ for scalar $\mu$. Assume that $\lambda=2$ is an eigenvalue of $A$ and its geometric multiplicity is at least $2$. What are the possibilities for the Jordan canonical form (JCF)?
What I know so far from the assumption is that
- the minimal polynomial of $A$ is of the form $f(x)=(x-2)^i(x+2)^j$ where $1\leq i\leq 3$ and $0\leq j\leq 2$.
- The number of blocks in the Jordan segment $J(2)$ is at least $2$.
One can write the possible minimal polynomial one by one, which gives the information of the size of the largest block in each Jordan segment, and use the possible geometric multiplicity of $\lambda=2$ to find JCF.
Here are my questions:
- Is there an alternative approach?
- Can we use the characteristic polynomial of $A$ here?
I would work with Jordan blocks directly, without going through minimal polynomial. It's a packing problem: we need to pack a size 5 matrix with blocks, of which
Denoting a block for brevity as $(\lambda)$, $(\lambda\lambda)$, $(\lambda\lambda\lambda)$ etc, we can work out the combinations, sorting them by the number of -2 entries present.
(-2) and a partition of 4 elements into at least two blocks. This means:
(-2-2) and a partition of 3 elements into at least two blocks.
Same as the previous one, but with (-2)(-2) instead of (-2-2).
(2)(2) and a partition of 3 elements into at least two blocks:
I don't think it could be simpler: the answer takes about as long to write out as the solution itself.