From trigonometry text:
Show that if $(a , b , c)$ is a Pythagorean triple then so is $(ka , kb , kc)$ for any integer $k > 0$. How would you interpret this geometrically?
Can someone please give a visual proof if possible?
From trigonometry text:
Show that if $(a , b , c)$ is a Pythagorean triple then so is $(ka , kb , kc)$ for any integer $k > 0$. How would you interpret this geometrically?
Can someone please give a visual proof if possible?
Copyright © 2021 JogjaFile Inc.
Edit: The formula answer makes it easy:
For a,b,c; $c^2 = a^2 + b^2 $. To verify ka,kb, and kc: $(ka)^2 + (kb)^2 = (kc)^2 $
$$(kc)^2 = k^2(c^2) = k^2(a^2 + b^2) = k^2a^2 + k^2b^2 = (ka)^2 + (kb)^2 $$
Here's a simple visual answer. You were correct, if the sides are proportional, then the triangles are similar. So, here are two 3/4/5 triangles, one in metric and one in inches: