If $A=\frac{D}{BC}$, with $B$, $C$, $D$ to at most two decimal places, then to how many places do I round $A$ so that $ABC$ returns $D$ to two places?

Question

I have an equation $$\frac{D}{BC} = A$$

• $B$ is any positive number (inclusive) between $0.01$ and $999.99$ (never more than $2$ decimal places)

• $C$ is any positive number (inclusive) between $1.00$ and $2.00$ (never more than $2$ decimal places)

• $D$ is any positive number (inclusive) between $0.01$ and $999,999.99$ (never more than $2$ decimal places)

For all possible values $B$, $C$, and $D$, what is the smallest number of decimal places that I can round $A$ to such that when I re-multiply it by $B$ and $C$, and round the product to two digits, it always equals the original $D$. (How do I find that?)