If $A∈M_{2×2}(R)$ is a matrix that follows this condition $A^1+A^2=I_2$
show that, matrix A is invertible
2026-03-28 08:50:10.1774687810
If $A∈M_{2×2}$ is a matrix that follows this condition $A^1+A^2=I_2$ show that A is invertible
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Hint: $(A^{2019}+A^{2018})A=A^{2019}(A+I)=A^{2020}+A^{2019}=I$ gives inverses for $A$ and $A+I$.