Let $m$ be the upper bound of $A$. Then, $a \leq m$ for all $a\in A $.
Now I should maybe find a way to show that that inequality is in fact an equality. Or maybe there's an easier way that I don't see.
Thank you in advance.
2026-03-25 11:11:46.1774437106
If an ordered rng $A$ has a upper or lower bound, then $A = {0}$
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Hint: what can you say about $m + m$?