If closed lambda calculus expression $M$ doesn't have a normal form, can $λx.λy.(M (x y))$ have a normal form?

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I'm trying to solve the following problem, but I'm not sure if it's actually possible/true:

"Let $M$ be a closed pure lambda term without normal form. Prove that $\lambda x.\lambda y.(M (x y))$ has no normal form either".

The similar problem with $\lambda x.(M x)$ can be proved trivially by eta-reduction; does this automatically imply the proof of my problem?

If $\lambda x.\lambda y.(M (x y))$ can have a normal form, can you give a counterexample expression $M$?