If $f:\mathbb R \to\mathbb{R}^3$ is class $C^1$ and regular at t then $f$ has a strong tangent at $t$

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I'm reading Elements of Geometry for Manfredo Do Carmo and I'm stucked in this problem. The book define the strong tangent: $f$ has a strong tangent at $t$ if the line determined by $f(t+h), f(t-k)$ has a limit position when $h,k\to 0$

I'm tried to show that $f$ has a unique tangent at $t$, in this case the strong tangent is the same as the weak tangent.

I think if f has two tangents then the continuity of f′ is broken...but I don't know how show that...

If we consider the curve $f(t)=(t^3,t^2)$, $f$ doesn't have strong tangent at $t=0$ because we can aproach the tangent $L=\{(\alpha,0):\alpha\in\mathbb{R}\}$ by the lines determined by the points $(h^3,h^2),(-h^3,h^2)$

But that lines aren't tangent lines and the line $L$ is impossible to aproach by tangent lines.

Then the regularity is crucial, I don't understand how it that works in the general case.