I never learned this in class. Given: $$3^{6x}+3^{-6x}+3^{2x+1}+3^{-2x+2} = 27 $$ If a and b are the solutions, then the value of: $$ \frac{2(a+b)}{3^{a} + 3^{b}}$$ are ....?
I tried to let $p=3^{2x}$, then the equation become $p^3 + \frac{1}{p^3} + 3p + \frac{9}{p} = 27$, and multiplying this with (p³): $$ p^6 + 3p^4 - 27p^3 + 9p^2+1=0$$ And finally, i stuck here. Give any idea to help me, please?