If $S_n$ denotes the sum of $n$ terms of an Arithmetic Progression (AP), then its common difference is given by:
$a$. $S_{n} - S_{n-1} - S_{n-2}$
$b$. $S_{n} -3S_{n-1} - 2S_{n-2}$
$c$. $S_{n} + 2S_{n-1} - S_{n-2}$
$d$. $S_{n} - 2S_{n-1} + S_{n-2}$
I know that the sum of $n$ terms of AP having first term $a$ and common difference $d$ is given by: $$S_{n}=\dfrac {n}{2} [2a+(n-1)d]$$
But I couldn't get any idea to solve.
$T(n)=S(n)-S(n-1)$
$T(n-1)=S(n-1)-S(n-2)$
$d=T(n)-T(n-1)$