Say I have a normed space $X$ and a Cauchy sequence $(x_n) \in X$. We can define $W$ to be an arbitrary subspace of X, with the Hamel Basis $\{e_1, e_2, e_3 ...\}.$
Given that $W$ is a subspace of $X$, we can define a Hamel Basis of $X$ as $$\{e_1, e_2, e_3 ... \}\cup\{e'_1,e'_2,e'_3...\}$$ From this, I think we can define unique sequences $(y_n)$ and $(w_n)$ such that $x_n = y_n + w_n$ for all $n \in \mathbb{N}$, and that $w_n \in W$ and $y_n \in \text{Span}(\{e'_1,e'_2,e'_3...\})$ for all $n$. Is it true then that for all normed spaces $X$, that $(y_n)$ and $(w_n)$ have to be Cauchy? $X$ and $W$ are not necessarily complete and not necessarily of finite dimension.
I think it's true, but in my attempts, I can't think of a way to get to where I need to go without using the assumption that $||y+w||\ge||y||,||w||$ for $y \in \text{Span}(\{e'_1,e'_2,e'_3...\})$ and $w \in W$. I don't think that inequality is true in general.
Either pointers or solutions would both be appreciated.
Consider $c_{00}$, the space of all finitely supported sequences equipped with $\ell^2$-norm and let $W = \operatorname{span}\{e_1\}$ and $Y = \left\{x \in c_{00} : \sum_{k=1}^\infty kx_k = 0\right\}$. Then $c_{00} = W \dotplus Y$. Let $$x_n = \left(1,\frac12, \frac13, \ldots, \frac1n, 0, 0, \ldots\right).$$ Then $(x_n)_n$ is Cauchy in $c_{00}$. The unique decomposition $x_n = y_n + w_n$ with $y_n \in Y$ and $w_n \in W$ is $$w_n = ne_1, \quad y_n = x_n - ne_1.$$ Neither sequence $(y_n)_n$ or $(w_n)_n$ is bounded so in particular they aren't Cauchy.