Does it mean anything if the function limit is 0/0 after performing some algebraic manipulation? it still is indeterminate, right? and would i determine such by just graphing it or ?
2026-03-26 14:29:03.1774535343
if the limit value is always indeterminate?
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You can test if a limit actually exists by computing one-sided limits. Example :
$\lim _{x\to 0^{+}}{1 \over 1+2^{-1/x}}=1$
${\lim _{x\to 0^{-}}{1 \over 1+2^{-1/x}}=0}$
If upper and lower bound are not equal then it simply doesn't exist.