If $log_2\,{x}$ lied between $(-2,2)$, then we could just substitute the extreme values in the logarithm, by equating $2$ to $log_2\,{2^2}$ and equating $-2$ to $log_2\,{2^{-2}}$
If via an inequality, we find the range of $log_2\,{x}$ to be $(-∞, -1)\cup(0,1)$, then how do we find the range of $x$?