If the third derivative of $\frac{x^4}{(x-1)(x-2)}$ is $\frac{-12k}{(x-2)^4}$ + $\frac{6}{(x-1)^4}$ then the value of k is?

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In the answers I found on google, see this link, they converted the given function into a certain form? What is the process of that conversion (I understand it is a partial fraction of sorts, but how to get there I do not know)? And in the subsequent steps, the factorial part made no sense to me either.

So yes, how do I proceed?

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welcome to MSE; As a hint:try like below $$\frac{x^4}{(x-1)(x-2)}=ax^2+bx+c+\frac{d}{x-1}+\frac{e}{x-2}$$ find $a,b,c,d,e$ then apply derivation. Remark: You can use dividing $x^4$ to $(x-1)(x-2)$ to simplify the fraction. It is not so hard to find $a,b,c,d,e$ for example if you think twice you will find $a=1$ and you can multiply both sides by $(x-1)$ and put $x=1 $ to find $d$ , and multiply bot sides by $(x-2)$ then put $x=2$ to find $e$