Let $T$ be a linear operator on an inner product vector space $V$. I'd like to prove that if $$(Tx|x)=0 \quad \forall x \in V$$ then $T$ is the null operator.
I can't figure out this proof using contradiction, do I have to choose an appropriate vector?
2026-04-08 20:47:31.1775681251
If $(Tx \mathbin{|} x) = 0$ for all $x$ then $T = 0$
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