I can't solve this problem. Someone please help! (I need Real Solution)
2026-04-01 04:22:49.1775017369
If $(x+y-3)^2 + (x-y-7)^4 = 0$, then find $x$ and $y$
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Hint:
Because squares of real numbers are non-negative, we have $x+y-3=x-y-7=0$.