Question :
If $|z-3i|+|z-4|=5$ then find the minimum value of $|z|$
What I did :
$$|z-3i| \leq |z|+3 \tag i$$
Also $$|z-4| \leq |z| +4 \tag{ii}$$
Now adding (i) and (ii) we get
$$ \Rightarrow |z-3i|+|z-4| \leq 2|z| +7 $$
$$\Rightarrow 2|z| +7 \leq 5$$
$$\Rightarrow |z| \leq -1 $$
Please suggest whether this is correct or wrong , also suggest the mistake thanks.
$$\Rightarrow |z-3i|+|z-4| \leq 2|z| +7 \\$$ $$\Rightarrow 2|z| +7 \leq 5$$
Here is the mistake. Plugging the value, you would get $5\leq 2|z|+7$ which would ultimately give you $ |z| \geq -1$ which is is kind of useless since $|z| \geq 0$
Hint: Notice that the distance between $(0,3i)$ and $(4,0)$ equals $5$. If $z$ has to satisfy $|z-3i|+|z-4|=5$, then it has to lie on the segment joining $(0,3i)$ and $(4,0)$. When $z$ varies on the aforesaid line, its distance from origin (i.e, $|z|$) will be minimum if $z$ is the foot of perpendicular drawn from origin on the line segment.