Let $g:\mathbb{R}^{3}\to \mathbb{R}^{3}$ be defined by $g(x,y,z)=(3x+4z,2x-3z,x+3y)$ and let $s={\{(x,y,z)\in \mathbb{R}^{3}:0\leq x\leq 1 ,0\leq y\leq 1 , 0\leq z\leq 1 }\}$. if
$\iiint_{g(s)} (2x+y-2z)dx dy dz=\alpha\iiint_{s} z dx dy dz $ then calculate value of $\alpha$??
what I did is: I substituted $x,y,z$ values from $g(x,y,z)$...in the equation ..but I dint get the correct anwer