I have just started studying implication in mathematics. So, you'll probably have an idea of where my confusion lies right from the get go.
In the truth table, where $A \implies B$ we obtain this result:
A | B |A->B
___________
T | T | T
T | F | F
F | T | T
F | F | T
Now, my confusion here is regarding why $A\implies B$ given A is false, and B true. The others I understand. The first and last one are obvious, the second one implies, to me anyway, that given A implies B, the truth of B rests upon the truth of A, B is false, A is True, which cannot be, thus not B given A is false.
Now... then, why is B true despite the fact that A is false? Or rather, why is the statement B given not A, True. The truth of B is implied from the truth of A, but A is a false statement. So it's very contradictory that this may be, and in fact, if you go through a real life example, you would find that the third statement seems to be false.
Say $A$ is the statement that it is dark outside, and $B$ the statement that the sun is not on our side of the earth. If it is not dark outside, than stating that the sun is on the other side of the planet must be wrong (in my example i'm going to claim that the sun is the only light source).
Side note:
I just had a thought, if A is false, does that mean you can conclude... mmm, whatever? I mean, B is implied via the truth of A, if A is false, B is NOT implied, but then B could be EITHER true or false, I suppose. Is this correct?
However, would that not mean that A does not imply anything when false. Would that not set the 3rd and 4th statement to be undefined?
The key here is the difference between $A \Rightarrow B$ (A implies B) and $A \Leftrightarrow B$ (A implies B and B also implies A). Consider the logical statements $A$ = "it is night" and $B$ = "I cannot see the Sun". $A$ implies $B$ here (if it's night I can't see the Sun, at least from this part of the Earth), but $B$ does not imply $A$: it could be cloudy, or an eclipse, or I could be indoors, et cetera.
The statement $A \Rightarrow B$ doesn't make any claim about whether $B$ also implies $A$. Defining it this way makes certain things a lot easier, since we can now say (e.g.) $x>7 \Rightarrow x>5$. This is a true mathematical statement ($A \Rightarrow B$) for real $x$. In other words, $A \Rightarrow B$ is true. But what if we let $x=6$? Now $B$ is true but $A$ is false; yet you'd still agree that $A \Rightarrow B$ is true. It just so happens that $A$ is false in this one case; that doesn't impact the overall truth or falsehood of $A \Rightarrow B$.
And yes, this does mean that a falsehood implies anything. "If $2+2=5$, then I am a penguin" is a true implication. This is called "Ex Falso Sequitur Quodlibet" (from a false thing, anything you want results) or the "Principle of Explosion". If you assume a contradiction (i.e. something false also being true) you can derive anything else.