5 distinct different colored balls into 8 distinct bins and no bin contain more than one ball, how many ways can the balls be placed into the bins?
I got 8*7*6*5*4=6,720. But I am unsure if it is right. My thought process was that the first distinct ball can be placed in 8 bins, the second into 7 bins ect. and i used the product rule to multiply all the combinations together to get my answer. Any hints or help would be great thanks.