In these notes to see the effect of the rotation operator $R$, on slide 11, the calculation $\rho' = R\rho R^{\dagger}$ is performed. Why isn't the operator only applied to the state AS $\rho' = R\rho$?
2026-02-23 00:25:15.1771806315
In the Bloch representation why pre and post multiply by rotation operator?
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