In this figure find AC=x

Question

Can you find $AC$, when only the angle $DBC$ and $DEB$ are $90$ grades. I can't because I think they should give the angle $CAB=90$ grades too.

Answer 1

You are correct. Without $CAB$ being right, you can have $BC$ be a range of lengths, which means triangles $ABC$ and $DEB$ need not be similar.