Suppose $f(x)=\sin x$ then how can I know in which interval it is uniformly continuous. I can solve easily by prove $|f(x_2)-f(x_1)|<ε$ for $|x_2-x_1|<\delta$ but I can't understand the same function is not uniformly continuous on other interval
2026-05-11 02:42:38.1778467358
In which interval the function $f(x)=\sin x$ is uniformly continuous
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Since $f'$ is a bounded function, $f$ is uniformly continuous on $\mathbb R$ and therefore on every interval of $\mathbb R$.