Indices solving for $x$

Question

Sorry this is a simple question but I'm having difficulty with it .

$$2(16^{3x+2}) = 1 / 8^{5x-4}$$

I'm told to solve for $x$.

My working -

$$2(16^{3x+2}) = 1 / 8^{5x-4}$$

$$32^{3x+2} = 8^{-5x+4}$$

$$32^{3x+2} = 8^{-5x+4}$$

$$(2^5)^{3x+2} = 2^{3(-5x+4)}$$

$$5(3x+2) = 3(-5x+4)$$

$$15x + 10 = -15x + 12$$

$$30x = 2$$

$$x= 1/15$$

My answer is wrong .. Can I get some help or hint on where did I go wrong ?

Answer 1

$$2\cdot16^{3x+2}=\dfrac1{8^{5x-4}} \iff2^{1+4(3x+2)}=2^{-3(5x-4)}$$

$$\implies1+4(3x+2)=-3(5x-4)\iff x=?$$