Inequality which involves complex numbers and absolute values

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How can I solve the following inequality:
$|\frac{(1+(1-\theta)z)}{1-\theta z}| \leq 1$ ?
$z$ is a complex number. I have to find the values of $\theta$ for which the inequality is satisfied.

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Hint : Multiply both sides with $|1-\theta z|$. Then use the real and imaginiary part on both sides to calculate the absolute values.