Inequality with 4 absolute values

128 Views Asked by At

I am exploring the topic of absolute value inequalities and I am really wondering how to solve this inequality without graphing:

$$ |x|+2|x+1|-3|x+2|+4|x+3|≤7 $$

I know it is possible to solve it by considering all 16 cases for this equation, but that seems very unappealing to me. Do you guys see any smart solutions?

1

There are 1 best solutions below

1
On BEST ANSWER

So, for the answer, we can reduce the cases to 4 only, we can see from inequality that, x has to be less than 0, it cannot be more than or equal to it, you can verify yourself by putting in x=0!

After a minute or two of calculation, we come to know that x cannot be less than -4, so our domain to check has reduced to: -4 < x < 0.

Within this, we can check for 4 cases:

CASE I: -1 <= x < 0 Solving in this you will get: x E [-1,-0.5] EQ1....

CASE II: -2 <= x < -1 Solving this: x E [-1.5,1) EQ2....

CASE III: -3 <= x < -2 Solving this: x E [-3,-2.25] EQ3....

CASE IV: -4 < x < -3 Solving this: x E [-3.75,-3) EQ4....

By the union of all 4 equations, we get: x E [-3.75,-2.25] U [-1.5,-0.5]